Question

I am having a hard time with graphing solution of a system of inequalities.

y>(or equal to) -x+3
y<(or equal to) 3x+5

Answer 1

To graph y >= -x+3, follow these steps

Step 1) Graph y = -x+3

Step 2) Make the line a solid line

Step 3) Shade above this solid line (since you have a >= sign)

Answer 2

So a point would be (0,3) and then I go over 1 and down 3?

Answer 3

start with (0,3)

slope is -1, so you go down 1, over to the right 1 to get to the next point (1, 2)

Two points are: (0,3) and (1,2)

Plot them and draw a line through them

Answer 4

so I guess I am confused, the slope for the other one is 3x?

Answer 5

just 3

Answer 6

first point: (0,5)

use the slope 3 or 3/1 to start at (0,5), then go up 3 units and to the right 1 unit to get the next point (1, 8)

Next point: (1,8)

plot the two points, draw a straight line through them

Answer 7

and I am shading the area where they share points so that menas just that the area where both equations have points in that area

Answer 8

exactly, basically where the two shaded regions overlap

Answer 9

ok I am doing this online soetimes this just doesnt click but I really appreciate your help. got the right answear finally, was making it much more difficult than that thank you

Answer 10

you're welcome