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p=2L+W2 solve for W
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do you mean \[P=2L-W^2\]
its cool i got it
Sure thing!
P = 2L + W2 we have to "Isolate W" so it looks like W= ......... First we have to bring the 2L to the LHS(Left hand side) P-2L = 2L-2L + W2 P-2L=W2 Re-write it with W2 on the RHS. W2=P-2L W=(P-2L)/2
By "W2", do you mean \[W^2?\]
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yea i did dat my fault for not rightin it correctly
Then you can just divide the "power 2" across, you should take the square root of both sides.
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