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Mathematics 7 Online
OpenStudy (anonymous):

Help please? state the limit and if there is not limit say that limit doesn't exist.

OpenStudy (anonymous):

1) lim x-> -1 f(x) 2) lim x-> 2- f(x) 3) lim x-> 2+ f(x) 4) lim x-> 2 f(x) 5) lim x-> -2 f(x) 6) lim x-> 3f(x)

OpenStudy (anonymous):

@Outkast3r09 can u help please?

OpenStudy (anonymous):

@UnkleRhaukus can u help?

OpenStudy (unklerhaukus):

\[\lim\limits_{ x\to -1} f(x)\] is the height of the blue line above x=-1 on the x-axis

OpenStudy (unklerhaukus):

\[\lim\limits_{ x\to 2^-} f(x)\] is the height of the blue line above the point just before 2 on the x axis

OpenStudy (anonymous):

hmm ok

OpenStudy (anonymous):

so for the first one it will be -2?

OpenStudy (anonymous):

soo?

OpenStudy (unklerhaukus):

no. the blue line is crossing the axis at x=-1, so the height is zero here

OpenStudy (anonymous):

ohh okay

OpenStudy (anonymous):

so the limit will be zero?

OpenStudy (unklerhaukus):

yeah for the first one thats right

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

lemme try the second one

OpenStudy (anonymous):

so number 2 will be -1? right?

OpenStudy (unklerhaukus):

correct

OpenStudy (anonymous):

ohh i think i'm starting to get this

OpenStudy (anonymous):

hmm for number 3 will the open circle count?

OpenStudy (anonymous):

or will it be undefined?

OpenStudy (unklerhaukus):

\[\lim\limits_{ x\to 2^+} f(x)\] is where x is a little bit to the right of 2 so is a tiny bit to the right of the open circle

OpenStudy (unklerhaukus):

if you were looking for the limit as \[x\to 2\] and both circles were open then it would be undefined

OpenStudy (anonymous):

so it will be positive 2?

OpenStudy (unklerhaukus):

um check that again

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

positive 1?

OpenStudy (anonymous):

wait it will be -2

OpenStudy (anonymous):

did i get it?

OpenStudy (unklerhaukus):

nope

OpenStudy (anonymous):

okay i'm gonna try again

OpenStudy (anonymous):

it will be -3

OpenStudy (unklerhaukus):

how could it be negative?

OpenStudy (anonymous):

oh imeant positive 3

OpenStudy (anonymous):

so is that correct?

OpenStudy (unklerhaukus):

thats better

OpenStudy (anonymous):

ok so number 4 will be -1 ?

OpenStudy (unklerhaukus):

thats right, ( note that if the lower circle was open then it would be undefined)

OpenStudy (anonymous):

okay number 5 will be -2?

OpenStudy (unklerhaukus):

nope

OpenStudy (anonymous):

hmmm ohh ok so it will be undefined right?

OpenStudy (unklerhaukus):

im not sure how you are getting that/

OpenStudy (anonymous):

let me look it again

OpenStudy (anonymous):

it will be positive 2?

OpenStudy (anonymous):

am i right?

OpenStudy (unklerhaukus):

it looks more like 1.5 to me

OpenStudy (anonymous):

its close but it hasn't reached the line

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

how about the last one? its tricky

OpenStudy (unklerhaukus):

what do you think

OpenStudy (anonymous):

it will be it doesnt exist

OpenStudy (anonymous):

right?

OpenStudy (unklerhaukus):

why would you say that

OpenStudy (anonymous):

hmmm hold on

OpenStudy (anonymous):

it will be 3?

OpenStudy (anonymous):

did i get it?

OpenStudy (unklerhaukus):

a bit less

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

soo?

OpenStudy (anonymous):

are u there?

OpenStudy (unklerhaukus):

dosent look like 2 to me

OpenStudy (unklerhaukus):

look like about 2.5 to me

OpenStudy (anonymous):

ok thanks

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