Mathematics
7 Online
OpenStudy (anonymous):
Help please? state the limit and if there is not limit say that limit doesn't exist.
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OpenStudy (anonymous):
1) lim x-> -1 f(x)
2) lim x-> 2- f(x)
3) lim x-> 2+ f(x)
4) lim x-> 2 f(x)
5) lim x-> -2 f(x)
6) lim x-> 3f(x)
OpenStudy (anonymous):
@Outkast3r09 can u help please?
OpenStudy (anonymous):
@UnkleRhaukus can u help?
OpenStudy (unklerhaukus):
\[\lim\limits_{ x\to -1} f(x)\]
is the height of the blue line above x=-1 on the x-axis
OpenStudy (unklerhaukus):
\[\lim\limits_{ x\to 2^-} f(x)\]
is the height of the blue line above the point just before 2 on the x axis
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OpenStudy (anonymous):
hmm ok
OpenStudy (anonymous):
so for the first one it will be -2?
OpenStudy (anonymous):
soo?
OpenStudy (unklerhaukus):
no. the blue line is crossing the axis at x=-1, so the height is zero here
OpenStudy (anonymous):
ohh okay
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OpenStudy (anonymous):
so the limit will be zero?
OpenStudy (unklerhaukus):
yeah for the first one thats right
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
lemme try the second one
OpenStudy (anonymous):
so number 2 will be -1? right?
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OpenStudy (unklerhaukus):
correct
OpenStudy (anonymous):
ohh i think i'm starting to get this
OpenStudy (anonymous):
hmm for number 3 will the open circle count?
OpenStudy (anonymous):
or will it be undefined?
OpenStudy (unklerhaukus):
\[\lim\limits_{ x\to 2^+} f(x)\] is where x is a little bit to the right of 2 so is a tiny bit to the right of the open circle
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OpenStudy (unklerhaukus):
if you were looking for the limit as \[x\to 2\] and both circles were open then it would be undefined
OpenStudy (anonymous):
so it will be positive 2?
OpenStudy (unklerhaukus):
um check that again
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
positive 1?
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OpenStudy (anonymous):
wait it will be -2
OpenStudy (anonymous):
did i get it?
OpenStudy (unklerhaukus):
nope
OpenStudy (anonymous):
okay i'm gonna try again
OpenStudy (anonymous):
it will be -3
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OpenStudy (unklerhaukus):
how could it be negative?
OpenStudy (anonymous):
oh imeant positive 3
OpenStudy (anonymous):
so is that correct?
OpenStudy (unklerhaukus):
thats better
OpenStudy (anonymous):
ok so number 4 will be -1 ?
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OpenStudy (unklerhaukus):
thats right, ( note that if the lower circle was open then it would be undefined)
OpenStudy (anonymous):
okay number 5 will be -2?
OpenStudy (unklerhaukus):
nope
OpenStudy (anonymous):
hmmm ohh ok so it will be undefined right?
OpenStudy (unklerhaukus):
im not sure how you are getting that/
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OpenStudy (anonymous):
let me look it again
OpenStudy (anonymous):
it will be positive 2?
OpenStudy (anonymous):
am i right?
OpenStudy (unklerhaukus):
it looks more like 1.5 to me
OpenStudy (anonymous):
its close but it hasn't reached the line
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
how about the last one? its tricky
OpenStudy (unklerhaukus):
what do you think
OpenStudy (anonymous):
it will be it doesnt exist
OpenStudy (anonymous):
right?
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OpenStudy (unklerhaukus):
why would you say that
OpenStudy (anonymous):
hmmm hold on
OpenStudy (anonymous):
it will be 3?
OpenStudy (anonymous):
did i get it?
OpenStudy (unklerhaukus):
a bit less
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OpenStudy (anonymous):
2?
OpenStudy (anonymous):
soo?
OpenStudy (anonymous):
are u there?
OpenStudy (unklerhaukus):
dosent look like 2 to me
OpenStudy (unklerhaukus):
look like about 2.5 to me
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OpenStudy (anonymous):
ok thanks