Question

Express the given quantity as a single logarithm.
ln(1+x^2)+2/1lnx−lnsinx

Answer 1

That doesn't quite make sense. Is the '1' in front of the ln(x) doing something?

Answer 2

I am not sure this is how it shows..

Answer 3

I'm troubled with that. Maybe just ignore it.

ln(a) + ln(b) = ln(a*b)

ln(a) - ln(b) = ln(a/b)

What else do you need?

Answer 4

what do you mean

Answer 5

I mean that you should apply those principles to your original problem statement.

Answer 6

Is the expression [ln(1+x^2)+2] /[1ln (x)−ln(sinx)] what you intended when you posted ln(1+x^2)+2/1lnx−lnsinx ?

Answer 7

yes i made the confusion.