Question

is my integration wrong?

Answer 1

\[\int\limits_{0}^{5}(mg + 640x^3)dx\]

Answer 2

\[mgx +\frac{ 640(x)^4 }{ 4 }\]

Answer 3

Well, \[\frac{ 640 }{ 4 }=160\]

Answer 4

But your integration is correct.

Answer 5

ok :) thank you i'll work out again

Answer 6

Don't forget to evaluate on 0≤x≤5

Answer 7

@abb0t
my value for m=75kg and g=9,81m/s^2 but my answer isnt correct :/
its meant to be 9.625 x 10^4

Answer 8

can you please check whr i might be going wrong?

Answer 9

\[75(9,81)(5)+ 160(5)^4\]

Answer 10

ah! lol

Answer 11

i see my mistake, i am getting 1,036 x 10^5

Answer 12

which isnt too bad right?

Answer 13

It must be your algebra b/c I got 96325

Answer 14

ok i started with 160x5^4= 1 x 10^5
75(9,81)(5)=3,679 x 10^3

Answer 15

\[735(5)-160(5)^4 \approx 9.63 \times 10^4 \]

Answer 16

And don't 4get your units.

Answer 17

why is it minus?

Answer 18

my integral was mgx + 640x^4/4

Answer 19

FToC II (Fundamental Theroem of Calculus pt. 2)

Answer 20

so my integral is wrong?

Answer 21

Suppose f(x) is continuous (which it is) on [a,b] and also F(x) is any anti-derivative for f(x). Then, \[\int\limits_{a}^{b}f(x)dx= F(b)-F(a)\]

Answer 22

sorry to interrupt and stuff, but i was wondering, what topic of math is this?? I haven't learned it yet :/

Answer 23

\[[mg(5)+160(5)^4]-[mg(0)+160(0)^4]=mg(5)+160(5)^4-0\]

Answer 24

yes but you just wrote 735(5)-160(5)^4

Answer 25

Is the answer 96325? If so, then the problem must be a word problem and mayb an object is falling, hence 9.8 (gravity) must be negative?

Answer 26

yes its about an object falling

Answer 27

thank you! :)

Answer 28

nvm haha sorry to interrupt!!!! good luck :) @abb0t is awesome!!! haha

and i like ur new pic @abb0t :) bye-bye have a nice day!

Answer 29

@iheartfood this looks like Calculus I but it could also be mechanics-physics, and or Calculus II.

Answer 30

ohhh okay i see... yeah im not that far in math yet haha... and i tried messaging u earlier but i couldn't. :O why is that?? :O

Answer 31

tho I'm almost there!! I'm in pre cal/trig!! :)

Answer 32

shoot me a mention. I was getting too many msgs' requesting to answer math questions and or exam questions.

Answer 33

ohhh okay haha :P i was just wondering if u could possibly help me with some chem questions on Monday?? (i'm pacific time.. wbu?) cuz i have to go in a sec but I'm kinda stuck on them!!! :O

Answer 34

i have to do something tomorrow haha so i can't come online... or at least i don't think i can!! hahaha :P but yeahhh do u think if ur online and i post them, and tag you, could u please help me?? :)

Answer 35

anyways, just let me know or message me!! i gotta go but hopefully u can help later!! :) thanks!! bye-bye have a great day!

Answer 36

@abb0t hahaha thanks :)

sorry @bronzegoddess for interrupting ur question btw!! glad u got ur help tho cuz this looks CONFUSING!!

Answer 37

its ok @iheartfood :)

Answer 38

A solution using Mathematica is attached.

Answer 39

:O isn't mathematica like expesive?

Answer 40

Not if you are an active student or faculty.