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simplify each expression :
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|dw:1359250931912:dw|
thats to the 1/3 power.
all the numbers are to the power.
\[(27p ^{3}q ^{6}r ^{-1})\frac{ ^{1} }{ 3 }\]
What is the third root of 27?
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sorry about the delay , 3
And what is the third root of p^3?
p cubed ?
Yes. What is the third root of p cubed?
p ?
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\[\sqrt[3]{p^{3}}=\]
Yes p.
What is the third root of p to the sixth?
p?
no.
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\[\sqrt[3]{p^6} =\]
a little help ?
\[p ^{\frac{6}{3}}\]
p squared .
yes.
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okay.
When you raise to a power, you multiply the exponents.
okay.
\[(27p^3q^6r ^{-1})^{\frac{1}{3}}=3pq^2r ^{-\frac{1}{3}}\]
THANK YOU ! i understood it perfectly. these problems are made seem so hard but you made it so easy !
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Good for you!!
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