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Mathematics 9 Online
OpenStudy (anonymous):

simplify each expression :

OpenStudy (anonymous):

|dw:1359250931912:dw|

OpenStudy (anonymous):

thats to the 1/3 power.

OpenStudy (anonymous):

all the numbers are to the power.

OpenStudy (anonymous):

\[(27p ^{3}q ^{6}r ^{-1})\frac{ ^{1} }{ 3 }\]

OpenStudy (mertsj):

What is the third root of 27?

OpenStudy (anonymous):

sorry about the delay , 3

OpenStudy (mertsj):

And what is the third root of p^3?

OpenStudy (anonymous):

p cubed ?

OpenStudy (mertsj):

Yes. What is the third root of p cubed?

OpenStudy (anonymous):

p ?

OpenStudy (mertsj):

\[\sqrt[3]{p^{3}}=\]

OpenStudy (mertsj):

Yes p.

OpenStudy (mertsj):

What is the third root of p to the sixth?

OpenStudy (anonymous):

p?

OpenStudy (mertsj):

no.

OpenStudy (mertsj):

\[\sqrt[3]{p^6} =\]

OpenStudy (anonymous):

a little help ?

OpenStudy (mertsj):

\[p ^{\frac{6}{3}}\]

OpenStudy (anonymous):

p squared .

OpenStudy (mertsj):

yes.

OpenStudy (anonymous):

okay.

OpenStudy (mertsj):

When you raise to a power, you multiply the exponents.

OpenStudy (anonymous):

okay.

OpenStudy (mertsj):

\[(27p^3q^6r ^{-1})^{\frac{1}{3}}=3pq^2r ^{-\frac{1}{3}}\]

OpenStudy (anonymous):

THANK YOU ! i understood it perfectly. these problems are made seem so hard but you made it so easy !

OpenStudy (mertsj):

Good for you!!

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