Question

Write an equation for a line parallel to x+15=-5y passing through (0,4)

Answer 1

Parallel lines have the same slope,
First, you need to find the slope of the given line, then use that slope for the new line.
To find the slope of the given line, solve x + 15 = -5y for y. Then put it in slope-intercept form, which is y = mx + b. m is the slope.
Second, the equation of a line with slope m that passes through point (x1, y1) is
y - y1 = m(x - x1)
Try it, and ask for help if you need it.

Answer 2

Thanks,I need help putting x=15=-5y into slope intercept form

Answer 3

First, switch the sides, so you start with -5y on the left side.

Answer 4

Next, the only thing happening to the y is that it is being multiplied by -5. How do you undo a multiplication?

Answer 5

\[x+15 = -5y\]Divide both sides by -5 to give\[-\frac{x}{5} -3 = y\]Now switch the sides.

Answer 6

Umm I think that by dividing?? So will that mean that I'm dividing 15 by -5y??

Answer 7

Correct, divide both sides by -5

Answer 8

So then what will happen next to the x??

Answer 9

-5y = x + 15
Divide -5y by -5
Divide x by -5
Divide 15 by -5

Answer 10

OK I got -5-3=y ..?..?..?

Answer 11

wait wait! I checked it and it actually its suppose to be y=-1/5-3

Answer 12

-5y/(-5) = x/(-5) + 15/(-5)
y = -(1/5)x - 3

Answer 13

Remember to include the x on the right side.

Answer 14

YESSSSSSS!!!!!

Answer 15

Since the original equation is now written in slope-intercept form, y = mx + b, you can read the slope directly. It's the number multiplying x, which is m.
m = ?

Answer 16

m=4 so then that will mean that the final answer will be y=-1/5x+4 xD

Answer 17

Where did you get a 4 from y = -(1/5)x - 3?

Answer 18

Remember, the slope-intercept form is y = mx + b, where m, the number multiplying x, is the slope.

Answer 19

ohh ok then my bad