Question

Divide (5x3 – 6 – 5x) ÷ (10 + 5x) using synthetic division.

Answer 1

A.



x2 – 2x + 3, R 24


B.



x2 – 3x, R 44


C.



x2 – 2x + 3, R –36


D.



x2 – 3x, R –56

Answer 2

you know synthetic division???

Answer 3

no i dont .

Answer 4

ok lets start

Answer 5

ok

Answer 6

you have this
(5x3 – 6 – 5x) ÷ (10 + 5x)
if i re arrange the numerator (5x3 – 6 – 5x) to this 5x3+0x2-5x-6
do you agree with this???

Answer 7

yes

Answer 8

now write the coefficients of x3 , x2 , x and the constant which are
5 0 -5 6

Answer 9

now consider the denominator
(10 + 5x)
put it equal to zero we get
(10 + 5x) = 0
thus x = -10/5 = -2
=> x= -2
clear up to here???

Answer 10

if you are clear up to this point we can start the process of synthetic division

Answer 11

howd you get -10/5

Answer 12

look you have (10 + 5x)
if you put it equal to zero you will get
(10 + 5x) = 0
clear???

Answer 13

ok

Answer 14

subtract 10 from both sides we get
10-10+5x = 0-10
=> 5x = -10
clear??

Answer 15

oh okay. then divide -10 by 5 and get -10/5.

Answer 16

yes exactly and -10/5 results in -2

Answer 17

yeah

Answer 18

thus x = -2

Answer 19

now the actual process starts here

Answer 20

take the coefficients 5 0 -5 6
and the rest is on the drawing