Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <6, -1>, v = <7, -4>

Answer 1

First find the dot product of the two vectors.l

Answer 2

okay so the dot product is 46

Answer 3

yes. Now find the magnitude of each vector.

Answer 4

how do you do that?

Answer 5

if the vector is <2,5> the magnitude is:
\[\sqrt{4+25}=\sqrt{29}\]

Answer 6

sqrt 37 and sqrt 65

Answer 7

Now multiply the magnitudes.

Answer 8

And then divide the dot product by the product of the magnitudes. That quotient is the cosine of the angle between the vectors so hit your inverse cosine button.

Answer 9

20.3 degrees?

Answer 10

That's what I got.

Answer 11

Okay great thanks!

Answer 12

yw