Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

y + 2 = 1/3x – 5/3; (–4, 3)

Answer 1

y = –3x + 15
y = –3x – 9
y = –4x + 3
y = –1/3x – 11

Answer 2

i think it is b

Answer 3

Use the rule: if lines are perpendicular then m1*m2=-1, where m1 and m2 are the slopes of the lines.

The slope of your line is 1/3. With the rule you can work out the other slope.

Answer 4

Once you've got that other slope, you have this equation for tha line:

y=m2*x + b. To get b, use the given point: (-4,3), so set x=-4 and y=3.

Answer 5

If you do this calculation, you will see b is wrong...

Answer 6

im honestly so lost on this one.

Answer 7

1/3 * -3 = -1, so m2 = -3.

Equation: y=-3x+b. Point on line: (-4,3). Set x=-4, y=3:

3=-3*-4+b

so

3 = 12 + b

b = 3 -12 = -9.

Equation y = -3 x -9

Answer b IS right , I was WRONG! (Sorry...)