Question

what about 3x^3+9x^2+6x?
I get 3x(x^2+3x+12). Any further factoring I can do?

Answer 1

Woops maybe you made a small typo when you wrote your new factors out!
You should have \(\large 3x(x^2+3x+\color{orangered}2)\)

And yes you can factor a little bit more from there! :)

Answer 2

let me check that

Answer 3

sorry yes I have 3x(x2+3x+2)

Answer 4

So I get (x+2) (x+1) is this correct?

Answer 5

Yay good job \c:/

Answer 6

thanks for your help! @zepdrix