Here's a question for AriPotta, and for all of you! It may seem hard, but it's not, and I actually think it's quite fun, if you need help, just ask :)

The total of three cousin's ages is 48. Bobby is half as old as Jim and 4 years older than Bob. How old are the cousins?

Question

Here's a question for AriPotta, and for all of you! It may seem hard, but it's not, and I actually think it's quite fun, if you need help, just ask :)

The total of three cousin's ages is 48. Bobby is half as old as Jim and 4 years older than Bob. How old are the cousins?

anonymous · Answer

One is 11, one is 22 and one is 15

anonymous · Answer

no..

anonymous · Answer

Anyone got it?

anonymous · Answer

13, 26, 9

anonymous · Answer

good, dont tell how you got it tho...I want it to be a surprise

anonymous · Answer

$a=\frac12b=c+4$ which means we can write their ages all in terms of a: $b=2a$, $c=a-4$. The sum of their ages $a+b+c$ is $48$ i.e. $a+2a+a-4=48$; solve for $a$ by combining like terms to yield $4a-4=48$ which reduces to $a-1=12$, so $a=13$. Solve for our other ages $b$ and $c$ straightforwardly to yield $b=2(13)=26$ and $c=13-4=9$

anonymous · Answer

gosh...lol thats a lot of numbers there lol

anonymous · Answer

Bobby is 13, Jim is 26, and Bob is 9.

anonymous · Answer

good