The line that passes through the given point and is perpendicular to the given line in slope intercept form: (1,-9) 4x+8y=12
First, rewrite the line in slope intercept form.
Okay will it be um y=2x+3/2 ??? im not positive about it
Almost. Divide everything in the equation by 4 first.
And then isolate y.
Ok I did I got y=1/2x+3/2
Yup. So one trick with perpendicular equations is that the slope is always the negative reciprocal of the current slope.
So if your slope is 2, then the perpendicular slope is -1/2.
So in this case, your slope is 1/2, which means the perpendicular slope is -2.
Got it and is the slope always going to come up as a fraction?
Not necessarily, it depends on what your original slope was. If your original slope was a fraction, then the perpendicular slope may be an integer or a fraction, depending on what the fraction was. i.e. 10/7 would become -7/10 but 1/10 would become -10 And we know that the slope intercept form of a line is y = mx +b. Now we have the slope as well as a point. So substitute everything into the equation to find b.
b=-19/2
So now you know your slope and the value of b. All you have to do is put it in y = mx + b form!
so then the slope intercept form will be y=1/2x-19/2 ??
am i right?
Almost. Your original slope was 1/2, right?
yes
So the slope of the perpendicular line will be the negative reciprocal, which means it will be -2.
that'll mean it will y=-2-19/2 ??
You forgot the x, but yes.
WHOOHOO!! haha:) and lets say the slope will be -2 then what will the reciprocal be?
1/2
oh the reciprocal? The reciprocal is just -1/2
if you have a value n, then the reciprocal is just 1/n
thanks will you mind helping me in another problem?
I'll write it in another post though
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