please help...THE SUM OF THREE CONSECUTIVE INTERGERS IS 54. FIND THE NUMBERS

Question

unklerhaukus · Answer

the the smallest of the consecutive number be $n$

this makes the three consecutive integers $n,n+1,n+2$

so the sum of them will be

$$(n)+(n+1)+(n+2)$$

and we know the sum is $54$

so we have $$(n)+(n+1)+(n+2)=54$$

simplify this and solve for $n$

unklerhaukus · Answer

the the*  let the

anonymous · Answer

THanks you so much! I knew this type of formula would be somewhere

lettme figure it out and i'll get back to you

unklerhaukus · Answer

sure

anonymous · Answer

n+n+1+n+2=54
3n=54-1-2
3n=51
n= 17

anonymous · Answer

thanks so much!

anonymous · Answer

54divided by 3 is 18

anonymous · Answer

so by simply dividing, it wouldn't be the right answer, so u have to get a letter, and then get the formula

anonymous · Answer

thanks you, I have a math exam, and this really helped

unklerhaukus · Answer

you have found $n=17$

and we set the consecutive integers to be $n,n+1,n+2$
substitute $n$ and you'll have the numbers

anonymous · Answer

huh?
oh i thought i was done...ok

anonymous · Answer

17+18+19

anonymous · Answer

I didn't know i had to do that...consecutive means...one after the other not the smallest

anonymous · Answer

not the same*** not the smallest

unklerhaukus · Answer

yeah consecutive does mean one after the other 

finally you can check you solution 
does $17+18+19=54?$

anonymous · Answer

ok thank you