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25^(x-2)=125 solve for X
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Remember, 25 = 5² and 125 = 5³. Do you know the next step?
divide 5?
Well, no. Try to get base to be the same so we can cancel it.
we can multiply one by 3 and the other by 2 so we can get 5^6?
No, it'd mess equation up. Here, let me show you. \[\Large25^{x-2}=125 \Rightarrow (5^2)^{x-2} = 5^3\] See what I did?
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yes
Now, what's the next step?
do we try to get rid of 5^2?
or do we use log or ln
Just base. (5)
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?
i dont get it
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