Question

What is the equation, in standard form, of a parabola that models the values in the table?

x -2 0 4
f(x) 4 -6 70

a. y = 3x² + 4x – 6
b. y = 4x² + 3x – 6
c. y = 6x² + 3x – 4
d. y = –4x² – 3x + 6

Answer 1

if we put x= 0 in all the given equations we get
a) y= -6
b) y= -6
c) y= -4
d) y = +6
thus we can directly guess that our required equation is in the upper two equations

Answer 2

so then it's either going to be A or B

Answer 3

yes ofcourse now we have to plug in x = 2 and x = 4 in A and B
if these function that will give us the desired value will be our answer

Answer 4

sorry for my bad english

Answer 5

now lets try x = 2 in A and B

Answer 6

I'm not getting to work for B

Answer 7

for x = -2
a) y = 3(4) +4(-2)-6 = 12 - 8-6 = 4-6 = -2
now put x = -2 in b
b) y = 4(4)+3(-2) - 6 = 16-6-6 = 10 - 6 = 4
thus our function is B

Answer 8

Ohhh I see what I did wrong. oops. That makes sense now

Answer 9

Thanks for your help.

Answer 10

you are welcome