Find all the zeros of the equation. 27x^2 – 324 = –x^4

a. -3, -6i
b. 3, 6i
c. 3, -3, 6i, -6i
d. 3, -3, 6i, 0

Question

Find all the zeros of the equation. 27x^2 – 324 = –x^4

a. -3, -6i
b. 3, 6i
c. 3, -3, 6i, -6i
d. 3, -3, 6i, 0

anonymous · Answer

Can anyone help me understand this?

directrix · Answer

27x^2 – 324 = –x^4
or
x^4 + 27 x^2 - 324 = 0.

Begin by factoring x^4 + 27 x^2 - 324 into the product of two binomials.

anonymous · Answer

I'm not sure how to do that.

anonymous · Answer

I would follow directx steps to set the equation to zero,  but from there I would use the quadratic equation.  Do you know that one

anonymous · Answer

No I don't. I have really been struggling with Algebra 2. Not really understanding.

directrix · Answer

Can you factor y^2 + 27 y - 324 ?

directrix · Answer

You need two numbers that multiply to -324 and add to 27.

anonymous · Answer

to factor it, would it be: (y+36)(y-9)?

directrix · Answer

@JuanitaM 
How would you use the Quadratic Formula on this?

anonymous · Answer

|dw:1359401902292:dw|

plug in values of a,b,c and that is the answer...since the choices are imaginery - my first thoughts