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int [1, 4] dx/(x-2)^2 ?
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Substitute (x-2) = t
\[\int\limits_{1}^{4} \frac{ dx }{ (x-2)^{2} }\]
it should be infinite
its not integrable on [1,4] because of "the function has vertica retricemptote in this interval "
yes, how do i show that?
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but in complex you can calcute it !
Oh yes!
|dw:1359381351716:dw|
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