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(Pre-cal: law of cosines) Find the area of the triangle. A=47 degrees b=32ft c=19 ft @amistre64
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law of cosine is a general version of the pythag thrm
in this case: a^2 = b^2 + c^2 - 2bc cosA
when the angle given is 90 degrees this simplifies to: a^2 = b^2 + c^2 such that a is the hypotenuse
Oh, so I need to find a before I can do s=a+b+c/2 and plug in for are.
area*
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|dw:1359387445633:dw|
Then plug in s and the values of a, b, and c in the area formula. A=sqrts(s-a)(s-b)(s-c)
if you want to do herons formula then yes, you would need to know all the side lengths
Okay, well that's the only way I learned so I'm going to do it that way. But thank you! I needed a refresher :)
good luck :)
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Thanks. :)
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