What is the equation of the line that passes through the points (-3, 2) and (-5, 8)?

Question

anonymous · Answer

Find Slope.
$$m = \frac{ y2 - y1 }{ x2 - x1 }$$(-3, 2) and (-5, 8)
$$m = \frac{ 8 - 2 }{ -5 -(-3) } = \frac{ 8-2 }{ -5+3 }=\frac{ 6 }{ -2 }=-3$$

anonymous · Answer

Now put into Point-Slope form. 
y - y1 = m(x - 1)
 m is slope
 Substitute x1 and y1 for the given point's coordinates.

Slope of -3
(-3, 2)
y - 2 = -3(x - (-3))
y - 2 = -3(x + 3)

Now change into Slope-Intercept form.y = mx + b

y - 2 = -3(x + 3)
Distribute.
y - 2 = -3x - 9
Add 2 to both sides.
y = -3x - 7

anonymous · Answer

Sorry it took a while for me to finish up.

anonymous · Answer

Its ok can you help me with something else? @jazy

anonymous · Answer

Sure

anonymous · Answer

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