Please help? What is the solution set of |x – 2| + 4 = 3?
subtract 4 from both sides to get |x – 2| + 4 = 3 |x – 2| + 4-4 = 3-4 |x – 2| = -1 do you see what to do from here?
keep in mind that |x| is either 0 or some positive number since the absolute value represents distance so |x-2| is either 0 or some positive number
I don't know what to do next? Do I add 2 to both sides?
Well, since |x-2| must be zero or positive, for what values of x is it the case that |x-2| = -1 ?
|x-2| = -1 is basically saying "x is some number on the number line that is -1 units away from 2" is that possible?
No
\(|x-2|=-1\) stipulates \(x-2=-1\) and \(2-x=-1\).
since it's not possible, there are no solutions
Whoops, that's right, no possible solutions. Durr.
Oh! I see now. No wonder it didn't make sense... Ha ha thanks, guys!
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