solve for k. 1/8k + -6/5=4- -1/7k
Can you write that with parentheses or the equation editor? It isn't clear what you mean.
\[\frac{ 1 }{ 8 }k + \frac{ -6 }{5} = 4- \frac{ -1 }{7} \]
Okay, you can try to make a common denominator, or you could do the brute force approach which is to simply multiply each term by the product of all of the denominators (8*5*7). After you do that, you won't have any fractions left, and it should be easy to find the value of k. Try it, and I'll check your answer.
Oops, you dropped the k on the right hand side. \[\frac{1}{8}k + \frac{-6}{5} = 4 - \frac{-1}{7}k\]
can you help by showing me step by step?
Okay, let's multiply everything by 8*5*7: \[\frac{1}{8}k(8*5*7) + \frac{-6}{5}(8*5*7) = 4(8*5*7) - \frac{-1}{7}k(8*5*7)\]Then we cancel things out and get\[k*5*7-6*8*7 = 4*8*5*7+8*5*k\]or\[35k - 336 = 1120+ 40k\]Now subtract 35k from each side\[35k-35k-336 = 1120+40k-35k\]\[-336=1120+5k\]Subtract 1120 from each side\[-336-1120 = 1120-1120+5k\]\[5k=-1456\]Divide both sides by 5\[k=-\frac{1456}{5}\] Which is pretty strange, and makes me a bit suspicious that the problem wasn't exactly the one to be solved.
But it *is* the answer to the problem we solved :-)
thank you ;'D ure awesome.
what did i do wrong for this next EQUATION? \[\frac{ 1 }{ 2}x + \frac{ 1 }{ 4 }= -1 (\frac{ 5 }{ 6 }x +4)\] answer i got. x =12/7
And you think the correct answer is?
x= 12/7
Wait, you said you got x= 12/7, but that it was wrong.
I don't think 12/7 is correct. How did you do the problem? What was your first step?
multipyling the common denomionator 2*4*6 like the problem before.
Okay, that's a good start. When I do that, I get \[24x + 12 = -40x -192\]\[64x = -204\]
oh!!
so then the answer would be -3.187
Close, but not exactly. -3.1875.
Unless a numeric answer was requested (or this is a chemistry or physics problem), I personally would leave it as a simplified fraction, -51/16.
When in Rome, do as the Romans do...
\[1(x-2)+7=-7(x+2) solve x.\]
Okay, I would use the distributive property of multiplication to expand that. \[a(b+c) = ab + ac\] Then add and subtract terms from both sides to get x on one side, and a number on the other.
x= -2/15?
Well, if you put that back in the equation, do you get a true statement, or do you end up with something crazy, like 7 = 9?
actually i gott -19/8
That's better :-)
\[\frac{ 1 }{ 5 }x + \frac{ 1 }{3}=1(\frac{ 2 }{ 3 }x +2)\] my answer come out to be 35/3?
Don't think so.
but its 5*3*3
Multiply both sides by 15, I get \[3x + 5 = 10x + 30\] which means x < 0
-25=7x -25/7?
yes, that's correct
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