Ask
your own question, for FREE!
Mathematics
8 Online
find the derivative of sin[ln(cosx^3)]
Still Need Help?
Join the QuestionCove community and study together with friends!
chain rule 3 times. lol
In sin[ln(cosx^3)] is (cosx^3) meant to be (cos(x)) ^3 OR is it meant to be ( cos(x^3) ) ? They are not the same.
cos(x^3)
here: we start by taking the derivative of the outside function sin(u) where u = ln(cosx^3). This is equal to cos(u)*du/dx. Then, du/dx requires the use of the chain rule again, therefore du/dx = d/dx ln(v) where v = cos(x^3). This is equal to (1/v)*dv/dx. We have that dv/dx requires use of the chain rule as well, so dv/dx = d/dx cos(k) where k = x^3. This is equal to -sin(k)*3x^2. So the final answer all together is: cos(ln(cosx^3))*(1/cosx^3)*(-sin(x^3))*3x^2
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos:
Aye.. I need actually some help on the shading here.. if the light is from above too I just feel something is off.
kaelynw:
tried a lil smt, the arm is off but i like the other stuff
Countless7Echos:
I don't know just no sketch doodle day :p finished a video already so I'm pretty
Ferrari:
Depression Hi, it's me, Jordan (ferrari). It's supposed to be the Fourth of July but I feel kinda depressed and mad at myself for no reason.
5 hours ago
19 Replies
3 Medals
18 hours ago
27 Replies
3 Medals
2 days ago
9 Replies
2 Medals
2 days ago
13 Replies
1 Medal