Ask
your own question, for FREE!
Mathematics
15 Online
find the derivative of sin[ln(cosx^3)]
Still Need Help?
Join the QuestionCove community and study together with friends!
chain rule 3 times. lol
In sin[ln(cosx^3)] is (cosx^3) meant to be (cos(x)) ^3 OR is it meant to be ( cos(x^3) ) ? They are not the same.
cos(x^3)
here: we start by taking the derivative of the outside function sin(u) where u = ln(cosx^3). This is equal to cos(u)*du/dx. Then, du/dx requires the use of the chain rule again, therefore du/dx = d/dx ln(v) where v = cos(x^3). This is equal to (1/v)*dv/dx. We have that dv/dx requires use of the chain rule as well, so dv/dx = d/dx cos(k) where k = x^3. This is equal to -sin(k)*3x^2. So the final answer all together is: cos(ln(cosx^3))*(1/cosx^3)*(-sin(x^3))*3x^2
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
AsianPanda08:
I need help. What's the term for words that sound the same but have different meanings? i'm getting different answers.
Graysonunderwoods:
Have you even been beaten by a wet spaghetti noodle by your girlfriend because sh
Ferrari:
I Have Returned to Writing Music (by me) so if you don't know, I used to write songs on here and post them, some of them were lowkey corny though.
kaelynw:
tried a lil smt, the arm is off but i like the other stuff
Countless7Echos:
whaa this looks so silly, nothing is funnier then looking at how I draw my hands
2 seconds ago
6 Replies
0 Medals
15 minutes ago
48 Replies
1 Medal
44 minutes ago
34 Replies
2 Medals
31 minutes ago
15 Replies
2 Medals
32 minutes ago
12 Replies
0 Medals