Question

6 (f+1) -3 (f+2) = 3 (2f+3) +6

Answer 1

Use the distributive property to expand everything: \(a(b+c) = ab + ac\)
Then add and subtract terms from each side to collect all of the f's on one side, and a number on the other.

Answer 2

im still confused can u help me solve it

Answer 3

Okay, 6(f+1) = 6f + 6(1). Do that for the rest of the equation. Be careful: -3(f+2) = -3f + (-3)(2) = -3f -6.

Answer 4

so you are going to use foil.
you will get 6f+6-3f-6=6f+9+6
then you combine to solve for "f"

Answer 5

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Answer 6

6f + 6 -3f - 6 = 6f + 9 +6

Answer 7

Okay, now combine like terms. For example, the left side would be 6f - 3f + 6 - 6 which simplifies to 3f.

Answer 8

6(f+1)-3(f+2)=3(2f+3)+6

Multiply 3 by each term inside the parentheses.
6(f+1)-3(f+2)=6f+9+6

Add 6 to 9 to get 15.
6(f+1)-3(f+2)=6f+15

Multiply 6 by each term inside the parentheses.
6f+6-3(f+2)=6f+15

Multiply -3 by each term inside the parentheses.
6f+6-3f-6=6f+15

Since 6f and -3f are like terms, add -3f to 6f to get 3f.
3f+6-6=6f+15

Subtract 6 from 6 to get 0.
3f=6f+15

Since 6f contains the variable to solve for, move it to the left-hand side of the equation by subtracting 6f from both sides.
3f-6f=15

Since 3f and -6f are like terms, add -6f to 3f to get -3f.
-3f=15

Divide each term in the equation by -3.
-(3f)/(-3)=(15)/(-3)

Simplify the left-hand side of the equation by canceling the common factors.
f=(15)/(-3)

Simplify the right-hand side of the equation by simplifying each term.
f=-5