Question

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?

Answer 1

high school math or calculus ? o_O

Answer 2

Algebra 1 lol

Answer 3

02x+.04*2x=112
.02x+.08x=112
.10x=112
x=112/.10
x=$1,120 invested @ 2%.

2*1,120=$2,240 amount invested @ 4%.
Proof:
.02*1,120+.04*2,240=112
22.4+89.6=112
112=112

Answer 4

cool 'cuz every1 hates compound interest problem lmao

Answer 5

Let interest earned of 1st acc be I(1)=P(1)*R(1)*T
Let interest earned of 2nd acc be I(2)=P(2)*R(2)*T
where P(1)=x , P(2)=x+800 , R(1)=0.02, R(2)=0.04

I(1)+I(2)=92
0.02x+0.04(x+800)= 92
0.02x+0.04x+32=92
0.06x=60
x=1000=P(1)=amount invested in 1st acc

P(2)=x+800=1000+800=1800 = amount invested in 2nd acc