Question

in 2000 the world's population was 6.08 billion and was increasing at a rate of 1.21% each year write a function for world population does the function represent growth or decay

Answer 1

is it p(t)=6.08(1.0121)^t:growth?

Answer 2

If the rate at which something is changing is positive, then the function represents growth. Additionally, if you read the problem it says that the population is "increasing" which also implies a growth function.

The basic growth function is
\[A = Pe ^{r*t}\]
Where P represents your principal amount, which is 6.08 billion in this case.

e is just the constant e, which can be input through a calculator.

r is the rate at which your principal amount is changing, which is 1.21%. However, we can't put a percentage into this function, so we convert it into decimal form, which gives us .0121.

T is the time.

So your function is

A = 6.08*e^(.0121*t)

Answer 3

soo my answer was right? :)