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Mathematics 15 Online
OpenStudy (anonymous):

PLEASE HELP!! simplify the term w^2+2w-24 / w^2+w-30+8 / w-5

OpenStudy (anonymous):

what I've done so far is (w+6)(w+4) / (w+1)(w-30) + 8/w-5

OpenStudy (anonymous):

Is your equation \[\frac{ w^2 + 2w -24 }{ w^2 + w -30 } + \frac{ 8 }{ w-5 }\]

OpenStudy (anonymous):

yess

OpenStudy (anonymous):

If that's the case, the way you broke up \[w^2 + w - 30 \] is incorrect.

OpenStudy (anonymous):

If you multiply out the way you broke it up You get \[w^2 - 29w -30\]

OpenStudy (anonymous):

If you fix that, then you should be able to do the problem easily.

OpenStudy (anonymous):

w^2 + w - 30 is a part of the question..you still there?

OpenStudy (anonymous):

@CanadianAsian

OpenStudy (anonymous):

Yes But the correct factorization is \[(w+6)(w-5)\]

OpenStudy (anonymous):

oooh, I see..so what do I do after that? :)

OpenStudy (anonymous):

I cross out w+6 because it's on in denominator and other one? so it would be w+4 / w-5 + 8/w-5? what do I do next? :)

OpenStudy (anonymous):

You can add the numerators of fractions with the same denominators. so it should be (w+4 +8)/(w-5)

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