Question

x^2 + 4x +1 = 0
Solve using quadratic formula
Medals awarded :)

Answer 1

x^2+4x+1=
x^2+4x+4-4+1
=(x+2)^2-4+1

Answer 2

=(x+2)^2-3=0
so
x+2=+-sqrt3

Answer 3

Sorry I do not understand that.

Answer 4

Have done and i dont seem to get the right answer

Answer 5

-0.27 and -3.73 are the correct answers

Answer 6

x1 = -0.2679
x2 = -3.7321

Answer 7

but i dont know how to get to them.

Answer 8

sqrt3=1.73
so
x=-2+-1.73
x=-.27
x=-3.73

Answer 9

i need the whole method from substituting numbers into equation of x=-b etc

Answer 10

\[\frac{ -b+-\sqrt b^2-4ac }{ 2a }\]

\[\frac{ -4+-\sqrt (4)^2-4*1*1 }{ 2*1 }\]

\[\frac{ -4+-\sqrt 12 }{ 2 }\]

\[x1=\frac{ -4+\sqrt12 }{ 2 }, x2=\frac{ -4-\sqrt12 }{ 2 }\]

Answer 11

Thanks! :)

Answer 12

My Pleasure.