Question

Help with a horizontal asymptote??

Answer 1

whatcha got?

Answer 2

well I am trying to figure out what to put in the equation \[y= \frac{ a^n }{ b^m }\]

Answer 3

The equation is 7x^2-3x-9/2x^2-4x+5

Answer 4

hopefully theres more instructions than that ;)

Answer 5

there it is

Answer 6

and I take it you need to determine the HA?

Answer 7

yes since n=m

Answer 8

HAs tells us what happens for very large values of x; and as such the addons after the first terms are usless since they contribute nothing to the equation so reduce this set up to:

7x^2
-----
2x^2

now, as x gets larger and larger you can see that x^2/x^2 really cancels out and we are left with?

Answer 9

7
-
2

Answer 10

7/2 yes. so that has to be the HA

Answer 11

alright and I have another one, but I think I know it now.
3x^2-4x-3/2x^2-3x+2

Answer 12

so it would be
3
-
2

Answer 13

very good :)

Answer 14

thank you! :)