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Find the slope of the line tangent to the curve r=1−sin(θ) at (1/2,π/6)
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we have a formula to calculate it. I change theta by a to easy typing 1st: dr/d(theta) = -cos(a) (take derivative your curve
the formula to calculate dy/d(x) = [(dr/d(a)) sin(a) + r cos (a)] /[ (dr/d(a))cos (a)-rsina)]
wait few minute, if you still want to get the answer, I have to use other way to type out to make sure that you understand what i am doing. I don't want to give you the result. you must know the logic how to get it. I guess your level is high enough to have that problem. Is it ok?
Hope this help
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