Question

Simplify: negative nine raised to the tenth power times negative nine raised to the negative third power

negative nine raised to the thirteenth power

nine raised to the seventh power

nine raised to the negative thirtieth power

negative nine raised to the seventh power

Answer 1

(-9)^10 x (-9)^-3
if you have the same base (in this case -9) then you will just add the exponents

therefore it equals (-9)^7

Answer 2

in which expression should the exponents be subtracted?

the quantity six raised to the tenth power raised to the negative seventh power

two raised to the ninth power divided by five raised to the ninth power

the quantity negative one-half raised to the eleventh power times the quantity negative one-half raised to the fourth power

three raised to the eighth power divided by three raised to the fifth power

Answer 3

can you help me with this too?

Answer 4

@privetek

Answer 5

in the first one you would have to multiply the exponents because its (x^a)^b
in the third one you would add the exponents

in the 2nd and 4th one you would subtract the exponents because it's a division problem.
-> x^a/x^b = a-b

Answer 6

opps.. 2 isn't included because it has different bases however 4 has 3 as a base
so it's just 4.. sorry

Answer 7

so its the last one?

Answer 8

yes

Answer 9

okay thanks so much!!!