Question

P^2-4p-32/p+4
@ghazi
–p + 8; p ≠ –4
p – 8; p ≠ –4
–p – 8; p ≠ –4
p + 8; p ≠ –4

Answer 1

well \[P^2-4p-32=(p-8)(p+4)\]

Answer 2

\[\frac{ (p-8)(p+4) }{ (p+4) }=(p-8)\] p=/ 4

Answer 3

confused

Answer 4

@Gungirl4ever1994 clear?

Answer 5

i no =/4
bc thats at the end of em all

Answer 6

sorry \[p \ne 4\]

Answer 7

b

Answer 8

bubba help on more?

Answer 9

keep posting :)

Answer 10

???

Answer 11

\[\frac{ q^2+11q+24 }{ q^2-5q-24 } =\frac{ (q+8)(q+3) }{ (q-8)(q+3) }=\frac{ (q+8) }{ (q-8) }\]

Answer 12

C

Answer 13

you can do this one :) you need to factorize

Answer 14

plzzz

Answer 15

yes you can do it :D z^2+3z+2=(z+2)(z+1)

Answer 16

A

Answer 17

thanks talk to you in a bit :)