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Mathematics 17 Online
OpenStudy (anonymous):

centre of gravity of r= a cos2theeta

OpenStudy (anonymous):

is this a disc?

OpenStudy (anonymous):

what disc

OpenStudy (anonymous):

centre of gravity of what?

OpenStudy (anonymous):

oh now i get it...u want the centre of the shape of the graph

OpenStudy (anonymous):

co-ordinated it includes

OpenStudy (hba):

Do you have a diag?

OpenStudy (anonymous):

i dont hav tht is y iam asking

OpenStudy (anonymous):

tell us the whole question

OpenStudy (anonymous):

its a four-petalled flower

OpenStudy (anonymous):

it is find the centre of gravity of r= a cos2 th\[a \cos 2\theta \]

OpenStudy (anonymous):

by symmetry its at the origin

OpenStudy (anonymous):

any limits on theta?

OpenStudy (anonymous):

no

OpenStudy (hba):

Its gonna be a hyperbolic paraboloid.

OpenStudy (anonymous):

4 petalled rose cntred at origin

OpenStudy (anonymous):

ya i hav seen through google but how can i fint its centriod

OpenStudy (anonymous):

i gt the answer

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