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Parth (parthkohli):
What'd the last digit of the expansion of \(2^{12n} - 6^{4n}\) be? I know that it is \(0\) by trying out \(n = 0\), but a more formalized approach would be...?
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Parth (parthkohli):
\[2^{12n} - 2^{4n}3^{4n}\]Then\[2^{4n}(2^{8n} - 3^{4n})\]What next?
Parth (parthkohli):
Modulo 10?
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