5 ping-pong balls with a total surface area of 320πcm² are placed side by side in a long box. Find the length, in cm of the box. (Answer given in the book is 40cm.) Please help thanks! TT
|dw:1359656793111:dw|So the length of the tube will be 5 times the diameter of the balls.
Or in other words, 10 times the radius.
The Surface Area equation involves the radius of the spherical object. I'll bet we can solve for the radius and then find the length! :)
Here is our equation for surface area. \[\large A_s=4\pi r^2\] They told that the TOTAL surface area of the balls is \(320\pi\). If we divide that value by 5, we'll get the surface area for just 1 ball.
So we can set it up like this. Here is the surface area of `one ball`.\[\large \frac{320\pi}{5}=4\pi r^2\]From here, we can solve for r to find the radius of `one ball`.
Dividing each side by 4pi gives us,\[\large \frac{320\pi}{20\pi}=r^2\]Which simplifies to,\[\large 16=r^2\]Taking the square root gives us the radius of each ball. Then we would want to multiply by 2 to get the diameter of each ball. Then multiply by 5 to get the length of 5 balls (the length of the box).
Thanks so much I understand now! XD
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