Question

A rectangular field is two times as long as it is wide. If the perimeter of the field is 600, what are the dimensions of the field? Write and eqation using only 1 variable(w) to answer the given question. Let w be the width of the field.

Answer 1

The answer to this is just like the second way I wrote the previous problem. Can you do it?

Answer 2

Let L = length
Let W = width

two times as long as it is wide: L = 2W
perimeter of the field is 600: P = L + L + W + W = 2L + 2W = 600, so
2L + 2W = 600, but L = 2W, so
2(2W) + 2W = 600
4W + 2W = 600
6W = 600

Answer 3

Can you rewrite the way you did the other problem please?

Answer 4

Oh thanks @mathstudent55

Answer 5

Writing it terms of W:

Perimeter = 2*length + 2*width, but length is 2*width
P = 2*(2*W) + 2*W = 6W = 600
W = 100
L = 2*W = ?

Answer 6

So L=200 and W=100?

Answer 7

Bingo.

Answer 8

Checking the result:
100 + 100 + 200 + 200 = 600

Answer 9

Thank you so much. You're awesome :D