Find an equation of the line that passes through the point (5, 4) and is perpendicular to the line
8x + 7y − 3 = 0.
(Let x be the independent variable and y be the dependent variable.)

Question

Find an equation of the line that passes through the point (5, 4) and is perpendicular to the line
8x + 7y − 3 = 0.
(Let x be the independent variable and y be the dependent variable.)

anonymous · Answer

so far i have y=-8/7x+3/7

tkhunny · Answer

This gives the slope of the given line.
Now, you must find the slope of the desired line, given that it is perpendicular to the first.

anonymous · Answer

isnt dht da slope? da answer dht i jst gave?. what do i do with dht answer afterwards?

tkhunny · Answer

No.  That is the slope of the given line.  That is NOT the slope of the line you need.  The line you need is Perpendicular to this line.  There is a relationship between the slopes of two perpendicular lines.  Do you know it?

anonymous · Answer

ummm no ..isnt it pose 2 b da inverse r sumfin like dht?