Question

Solve the given equation by using the quadratic formula.
2x2 - 3x - 4 = 0. What value is under the radical in your answer?

Answer 1

\[2x^2-3x-4=0\]
\[ax^2+bx+c=0\] so
\[a=2,b=-3,c=-4\] use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 2

\[x=\frac{-(-3)\pm\sqrt{(-3)^2-4\times 2\times (-4)}}{2\times 2}\]
\[x=\frac{3\pm\sqrt{9+32}}{4}\]etc

Answer 3

ok

Answer 4

you are only one step away, hope all the rest of the steps were clear

Answer 5

they were