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Find the zeros write in factored form f(x)=7x^3-x^2+7x-1
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if u put 1/7 in the equation u get 0 means 1/7 is a root so x=1/7 or 7x-1 is a factor now divide the equation by 7x-2 to get other factors
You have to find the zeros first
factors first then from that u find zeros
So divide the whole equation by 7x-2
You can find the zeros by factoring: \[(7x^3 - x^2 ) + (7x - 1)\]Are there any common factors in the left hand parentheses? Factor them out.
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After doing that, you should be able to factor again by using the distributive property in reverse: \[ab + ac = a(b + c)\]except here the factor will be a binomial.
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