Find the zeros write in factored form f(x)=7x^3-x^2+7x-1

Question

anonymous · Answer

if u put 1/7 in the equation u get 0 means 1/7 is a root
so x=1/7 
or 7x-1 is a factor

now divide the equation by 7x-2 to get other factors

anonymous · Answer

You have to find the zeros first

anonymous · Answer

factors first then from that u find zeros

anonymous · Answer

So divide the whole equation by 7x-2

whpalmer4 · Answer

You can find the zeros by factoring:

$$(7x^3 - x^2 ) + (7x - 1)$$Are there any common factors in the left hand parentheses?  Factor them out.

whpalmer4 · Answer

After doing that, you should be able to factor again by using the distributive property in reverse:
$$ab + ac = a(b + c)$$except here the factor will be a binomial.