Question

Calculus:

Answer 1

What is: \[\int\limits_{?}^{?}xe ^{-x ^{2}}dx\]

Answer 2

thank you. can u please explain how you go that?

Answer 3

yes, first use u-substitution so you let u = -x^2
du = -2xdx
xdx = -1/2du

-1/2 (integral sign) e^u du
= - (e^u) / 2 + C

= - (e^-x^2) / 2 + C

You can simplify that to:

- 1 / (2ex^2) + C

Understand?

Answer 4

yes! thank you!

Answer 5

no problem!