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Solve the triangle. A = 32°, a = 19, b = 12
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so you can find the size of angle B by using the law of sines \[\frac{\sin(32)}{19}=\frac{\sin(B)}{12}\] just solve for B when you have B you can find C by angle sum of a triangle to find the length of side c, use the law of sines again hope this helps
Why do I do (sin(32)/19) rather than (19/sin(32))?
you can... the law of sines works either way but the way I've written it, your unknown, B, is in the numerator
you will need to do it that way to find the side c
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