this equation 3x^4 - 4x^3 - 2x^2= 0 has three real solutions. can someone please tell me what they are?
x = 1/3 (2+sqrt(10)) x = 1/3 (2-sqrt(10)) x = 0
\[x \approx 0, 1.72, -0.39\]
so: x=0 x=1.72 x=-0.39
these figures dont work for me
my software wont accept them
umm what figures?
the 0, 1.72, -0.38
you might have to retype them, copying from this site isnt really the best on other softwares
And its not right to just copy and paste, its against the code of conduct.
i actually got the same answer when i did it myself and typed it into my software and it rejected so i came here to see if someone had a different answer
First, factor x^2 from every term.
hmm, sorry then, stupid response on my part. but if it helps, im getting the same thing, try more digits maybe...?
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