Question

find derivative of f(x)=(lnt +t)^(1/2)

Answer 1

you have this
f(x)=(lnt +t)^(1/2)
dy/dx = 1/2((lnt +t))^(-1/2) . d/dx((lnt +t))
do it now

Answer 2

I got that far on my own, my problem is simplifying the next step ... f'(x)=1/2(in t+t)^(-1/2) *(1/t+1)

Answer 3

did u get something like