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Mathematics 18 Online
OpenStudy (anonymous):

3x^2+1=-4x

OpenStudy (luigi0210):

Solve? factor?

OpenStudy (anonymous):

she wants us to solve by factoring or taking the square root

OpenStudy (luigi0210):

okay, well fist thing you would do is add the 4x to both sides, so it would be 3\[^{2}\]+4x+1

OpenStudy (anonymous):

okay

OpenStudy (luigi0210):

*3x^2+4x+1 The only factors that they have is 1 and 1 and there are 2 plus signs, so that means there are no negative signs

OpenStudy (anonymous):

so it woulf be (3x+1)(x+1)?

OpenStudy (luigi0210):

Yup, simple right?

OpenStudy (anonymous):

yeah, so then the answer would be x= 1?

OpenStudy (luigi0210):

no, it would be -1, and -1/3 Remember that the equations are x+1=0 and 3x+1=0 so to get x by itself you have to subtract them x=-1 and 3x=-1 Now you would divide by to get x by itself so it would be x=-1/3

OpenStudy (anonymous):

okay, i got it

OpenStudy (anonymous):

x^2-1=0

OpenStudy (luigi0210):

Do you like factoring or taking the square root better?

OpenStudy (anonymous):

factoring

OpenStudy (luigi0210):

Okay, so what do you think the factors of this one are? since it's negative it means it had to have a negative and positive number

OpenStudy (luigi0210):

Like the last problem, it has a 1, so the multiples are 1 and 1, but there is no x value so it has to be (x+1) and (x-1) when factored they equal x^2-x+x-1 The x's would cancel each other out and you would be left with x^2-1

OpenStudy (anonymous):

im confused

OpenStudy (anonymous):

so the final answer would be x^2-1?

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