write the expression in factored form? x^2+8x-xy-8y
Somebody please help me:)!!!!!!
try grouping like this first: \(\large x^2+8x-xy-8y \) = \(\large (x^2+8x)-(xy+8y) \) now do you see what you can factor our from each of the groupings (parenthesis) ????
*factor out
am i suppose to still work on that or is that the answer
i gave a hint so you can continue...
what else am i suppose to do to get the answer please help
look at the first grouping, \(\large (x^2+8x) \) do you see what you can factor out here? each term in this binomial has the common factor of x
will it be (x^2-1) ?
i dont know im so stupid ughh
no... notice that \(\large (x^2+8x)=(x\cdot \color{red}x+8 \cdot \color{red}x)=(x+8)\cdot \color{red}x \) ok... i factored the fist term for you... can you do the same for the second grouping: \(\large (xy+8y) \)
i tried working on it a bit now and i got something like x(x+8)
ok.... now do the second grouping from above....
so far i have -x(y-8) but that doesnt look right
no, it's not... what do both xy and 8y have in common?
y? so itll be y(x+8)?
correct... :)
ok i have that now how do i write my answer out?
one more step. so this is what we have so far: \(\large x(x+8)-y(x+8) \) look at the big picture... notice they both have (x+8) as a common factor... factor this whole thing out just as you did before...
i dont know how to factor it out.? can you help me:x
suppose I give you this as an example: \(\large xa-ya \) how would you factor this?
x(a) - y(a) ??? i really dont know how to do this and i even did the tutorial alot of times and still dont get it
both terms have "a" in common so factor that out: (x - y)a do you understand this part?
could it be (x-y)( x+8)
yes
yayyy thankss now i have like 9 more to go ughhh
Join our real-time social learning platform and learn together with your friends!