Question

find the real or imaginary solutions by factoring?
x^4 - 3x^2 = -2x^2

Answer 1

add 2x^2 to both sides
what you get??

Answer 2

hi there please re-state the problem i'm having problems analyzing what your really asking for?

Answer 3

find the real or imaginary solutions by factoring?
x^4 - 3x^2 = -2x^2

Answer 4

that's all it says

Answer 5

now add 2x^2 to both sides what you get???

Answer 6

its easy do it

Answer 7

thats not how you answer these questions. I will help you to get the correct answer. First we will use the factor theorem. Have you ever learnt about the factor theorem?

Answer 8

ok lets do it

Answer 9

you have this
x^4 - 3x^2 = -2x^2
adding 2x^2 to both sides we get
x^4-x^2=0
x^2(x^2-1)=0
now either x^2 = 0 or x^2-1 = 0
can you find the solution now???

Answer 10

x= -1. Plug in -1 for x in the equation and the equation will be equal to zero.

Answer 11

if x^2 = 0
then
x.x = 0
x=0 , x =0


if x^2 - 1 = 0
then x^2 = 1
x=+1 , x = -1
thus all the solutions are real
the possible solutions are
0,0,1,-1