Question

need help with this kind math problem

Answer 1

You know vectors?

Answer 2

sort of

Answer 3

Do you know the vector dot product?

Answer 4

yes i know that

Answer 5

Right. So think of the two edges of the pyramid as vectors. Then the cos of the angle between them can be calculated from the dot product between them.

Answer 6

236 and 146?

Answer 7

Redraw the pyramid. Align the base of the pyramid along the x and y axes.

Then the top of the pyramid has x,y ordinates of 230/2 and the z ordinate is 146

Now you can figure what those two vectors are

Answer 8

one sec

Answer 9

k

Answer 10

Here:

Answer 11

hmm i see

Answer 12

t is <230,0,0>

Answer 13

No. T is the top of the pyramid. It lies above the center of the base at a height in z direction of 146

Answer 14

P is the corner of the pyramid that lies along the positive part of the x axis

Answer 15

p is the same as q?

Answer 16

P and Q are two corners of the pyramid, distinct corners

Answer 17

k

Answer 18

(0,0,0) is one corner, (230,0,0) is P, ...

Answer 19

q 146 which is the heigh <146,0,0>

Answer 20

The solid green lines are the base of the pyramid. The coordinates of Q is
Q = (230,230,0)

Answer 21

Hence the four corners of the base of the pyramid are
(0,0,0)
(230,0,0) P
(230,230,0) Q
(0,230,0)

Answer 22

forget about the coordination of <x, y, z>

Answer 23

so qt= <-115, -115, 146>

Answer 24

Yes

Answer 25

getting a large numbers

Answer 26

pq*qt =21316

Answer 27

|pt|= 218.5

Answer 28

same for |qt|

Answer 29

Yes

Answer 30

@JamesJ |pt||qt| or pt*qt?

Answer 31

pt . qt is the dot product between those two vectors. The formula at the bottom links the dot product with the angle between them, alpha, which you want to calculate.