10th grade geometry hell please!!?
do you have a question?
here one if u could plz jus explain how i get the answer that would be great!!
i typed help lol somehow it put h*ll o.O
wait i was gonna help!
sorry lol thought u left :P so whats the first step to findin the answer?
ok so first you need to find the difference (use absolute value) between X1 and X2, so you get |2 - 18| = 16 Then the same for y |10 + 18| = 28 Now square both and add 16^2 + 28^2 = 1040 Then take the square root of 1040 That will give you the distance.
So would the answer be 1081600? how do i round this lol its a huge number
\[\sqrt{1040} = \] you should get like 30 something
oh! my bad fergot you have to type square root first on the calculator i got 32. a bunch of numbers so rounded would be 30? :D
nearest hundredth would mean you would round it to 32.25
oh ok, so then that would be my answer right?
yup!
:D thank you soooo much!
np! if you have any other questions just ask
ok and yea i do hang on a sec
k
alrighty how do i figure this one out?
hang on
ok
okay, it's 11.7 sry it took so long.
thanks :D can u tell me how u got it? that way i can learn to do this as well haha got a seg test comin up and nah thats ok
ya 1 sec
14 cos 60 + sqrt ( 13^2 - (14 cos 30)^2) = 11.7 Had to use the formula for the ASA theorem.
ok makes since, thats all for tonight, thanks again :)
sense*
no problem! just message me if you need help again.
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