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Mathematics 6 Online
OpenStudy (anonymous):

jane is cooking beans and rice for dinner tonight. she has 5 cans of black beans, 5 cans of red beans, and 1 can of garbanzo beans in her cupboard. if she grabs a can of beans without looking at the label what is the probability of her making black beans and rice for dinner? LAST QUESTION :D thanks for your help

OpenStudy (anonymous):

2 cans of black beans**

OpenStudy (kropot72):

What is the total number of cans of beans?

OpenStudy (anonymous):

8 in total.. 2 black, 5 red, and 1 garbanzo

OpenStudy (anonymous):

1/4

OpenStudy (anonymous):

u've said 10 in the question @geebear69

OpenStudy (anonymous):

i know .-. i did a typo

OpenStudy (anonymous):

so it is 2 in total

OpenStudy (anonymous):

I mean * 8

OpenStudy (kropot72):

So the probability of selecting a can of black beans is\[\frac{number\ of\ cans\ of\ black\ beans}{total\ number\ of\ cans}\] You should then simplify the result.

OpenStudy (anonymous):

1/4

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