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OpenStudy (anonymous):
That is a big subject. Did you have something in mind?
OpenStudy (anonymous):
um. parellel and perpendicular lines. like tell if an equation is parallel, perpendicular or neither.
OpenStudy (anonymous):
quetions like that
OpenStudy (anonymous):
im trying to practice for the interim so any question is basically good
OpenStudy (anonymous):
No problem. First how do you tell if an two lines, given their equations, are parallel or perpindicular?
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OpenStudy (anonymous):
if they're parallel then they will have the same slope but different y-intercepts. if they're perpendicular then they'll have opposite reciprocal slopes.
OpenStudy (anonymous):
You got it so tell me if these two equations are parallel, perpindicular, or neither
\[y=12x+4\]\[y=144x/12+13\]
OpenStudy (anonymous):
neither
OpenStudy (anonymous):
Try again
OpenStudy (anonymous):
aw
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OpenStudy (abb0t):
What is the equation of the line:
perpendicular to the line 4x + 5y - 20 = 0
and
passing through the point (8, -3)?
OpenStudy (anonymous):
if u divide 144 by 12 its 12 so it cant be..ooohh.its parallel
OpenStudy (anonymous):
You got it! Now try abbOt's
OpenStudy (anonymous):
i am
OpenStudy (anonymous):
so i solved 4x5y-20=0 and got y=-4/5x+4
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OpenStudy (anonymous):
is it right so far?
OpenStudy (abb0t):
slope, yes.
OpenStudy (anonymous):
is the y-intercet right?
OpenStudy (abb0t):
yes...
OpenStudy (anonymous):
wart?
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OpenStudy (anonymous):
and im not sure abut all those dots after ye
OpenStudy (anonymous):
yes
OpenStudy (abb0t):
wat did u mea by "is it y-intercept"?
OpenStudy (anonymous):
but either way then i substituted x and y with the point (8,-3)
OpenStudy (anonymous):
oih if it was right
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OpenStudy (abb0t):
well, what did you get as the equation of the line perpendicular?
OpenStudy (anonymous):
i still havnt finihed it. im making sure im doing it right so far.
OpenStudy (anonymous):
so i plugged in the points. i have -3=-4/5x8+4
OpenStudy (anonymous):
then i got -3=-32/5+4
OpenStudy (anonymous):
is it right so far?
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OpenStudy (abb0t):
Not quite.
OpenStudy (anonymous):
whats wrong?
OpenStudy (anonymous):
am i not supposed to have the 4?
OpenStudy (abb0t):
your slope is not quite correct.
OpenStudy (abb0t):
for the first part of the equation. It should be perpendicular.
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OpenStudy (anonymous):
so i should flip the slope before i plug in the points?
OpenStudy (anonymous):
i might be getting it but i want to know if i put 4 or b in the second part.
OpenStudy (anonymous):
i think its b now that i look at it
OpenStudy (anonymous):
so the equation would be y=5/4x-13
OpenStudy (anonymous):
The gradient of any line perpendicular to the line 3x-2y+12=0 is
\[a)\frac{3}{2}\]
\[b)-\frac{3}{2}\]
\[c)\frac{2}{3}\]
\[d)-\frac{2}{3}\]
Multiple choice. Choose the correct answer.
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